CogitaVerse

Heat Capacity | Specific, Molar, Cp, Cv, Cp – Cv = R, Ratio γ | Full Thermodynamics Guide

Heat Capacity: Complete Thermodynamics Guide

Specific Heat Capacity · Molar Heat Capacity · Cp vs Cv · Derivation of Cp – Cv = R · Ratio of Heat Capacities (γ)

Heat capacity (or thermal capacity) is an extensive property of matter that describes the amount of heat required to raise the temperature of a given mass of a substance by one unit (Kelvin or Celsius) without undergoing a phase change. It quantifies a material’s ability to store thermal energy.

\[ C = \frac{\Delta Q}{\Delta T} \]

where \(C\) is the heat capacity, \(\Delta Q\) is the heat supplied, and \(\Delta T\) is the resulting temperature change.

Specific Heat Capacity (s or c)

Specific heat capacity is the heat capacity per unit mass. It is defined as the amount of heat required to raise the temperature of one gram (or one kilogram) of a substance by one degree Celsius (or one Kelvin).

\[ s = \frac{C}{m} = \frac{1}{m} \frac{\Delta Q}{\Delta T} \]

Common units: J·g⁻¹·K⁻¹ or J·kg⁻¹·K⁻¹. Water has a high specific heat (4.184 J·g⁻¹·K⁻¹), making it excellent for cooling and thermal regulation.

Molar Heat Capacity (Cm)

Molar heat capacity is the heat required to raise the temperature of one mole of a substance by one Kelvin. It is related to specific heat by multiplying by the molar mass.

\[ Q = n \, C_m \, \Delta T \]

where \(n\) is the number of moles, \(C_m\) is the molar heat capacity (J·mol⁻¹·K⁻¹). For ideal gases, molar heat capacities are often given at constant pressure (\(C_p\)) or constant volume (\(C_v\)).

Molar Heat Capacity at Constant Pressure (Cp)

Cp is the heat required to raise the temperature of one mole of a substance by one Kelvin while keeping pressure constant. Using the first law of thermodynamics:

Derivation: First law: \(dq = dE + P\,dV\). Divide by \(dT\) at constant \(P\): \[ \frac{dq}{dT} = \frac{dE}{dT} + P\frac{dV}{dT} \] Enthalpy is defined as \(H = E + PV\). Differentiating at constant \(P\): \(dH = dE + P\,dV\). Hence: \[ C_p = \left(\frac{dH}{dT}\right)_P \] Thus, \(C_p\) is the temperature derivative of enthalpy at constant pressure.

Molar Heat Capacity at Constant Volume (Cv)

Cv is the heat required to raise the temperature of one mole of a substance by one Kelvin while keeping volume constant. At constant volume, no work is done (\(P\,dV = 0\)), so all heat goes into internal energy.

Derivation: From first law, \(dq = dE + P\,dV\). At constant volume, \(dV = 0\), thus: \[ C_v = \left(\frac{dE}{dT}\right)_V \] Hence, \(C_v\) is the temperature derivative of internal energy at constant volume.

Detailed Derivation of Cp – Cv = R for an Ideal Gas

This is one of the most important relations in thermodynamics. We derive it step by step.

Step 1: Start with the first law of thermodynamics for a closed system: \[ \Delta Q = \Delta U + \Delta W \] where \(\Delta Q\) is heat added, \(\Delta U\) is change in internal energy, and \(\Delta W\) is work done by the system. For a gas, \(\Delta W = P \Delta V\) (pressure-volume work). Thus, \[ \Delta Q = \Delta U + P \Delta V \]
Step 2: For a constant pressure process, the heat added is \(\Delta Q = n C_p \Delta T\). The change in internal energy is \(\Delta U = n C_v \Delta T\) (since internal energy depends only on temperature for an ideal gas). Substitute: \[ n C_p \Delta T = n C_v \Delta T + P \Delta V \]
Step 3: Use the ideal gas law \(PV = nRT\). For a constant pressure process, \(P\) is constant. Consider two states at temperatures \(T_1\) and \(T_2\): \[ P V_1 = n R T_1, \quad P V_2 = n R T_2 \] Subtract the first from the second: \[ P (V_2 – V_1) = n R (T_2 – T_1) \] That is, \(P \Delta V = n R \Delta T\).
Step 4: Substitute \(P \Delta V = n R \Delta T\) into the equation from Step 2: \[ n C_p \Delta T = n C_v \Delta T + n R \Delta T \]
Step 5: Cancel \(n \Delta T\) (non-zero): \[ C_p = C_v + R \] Final relation: \[ C_p – C_v = R \] where \(R = 8.314\ \text{J·mol}^{-1}\text{·K}^{-1}\) is the universal gas constant.

Ratio of Heat Capacities (γ)

The ratio of \(C_p\) to \(C_v\) is an important dimensionless quantity denoted by \(\gamma\) (gamma).

\[ \gamma = \frac{C_p}{C_v} \]

For monatomic ideal gases, \(\gamma = 5/3 \approx 1.67\); for diatomic gases at moderate temperatures, \(\gamma = 7/5 = 1.4\); for polyatomic gases, \(\gamma\) is closer to 1.33 or lower. This ratio appears in adiabatic processes: \(PV^\gamma = \text{constant}\).

Table of Molar Heat Capacities of Common Gases (at 25°C, 1 atm)

Gas\(C_p\) (J·mol⁻¹·K⁻¹)\(C_v\) (J·mol⁻¹·K⁻¹)\(\gamma = C_p/C_v\)
Helium (He) – monatomic20.7912.471.67
Argon (Ar) – monatomic20.7912.471.67
Nitrogen (N₂) – diatomic29.1220.791.40
Oxygen (O₂) – diatomic29.3820.951.40
Carbon dioxide (CO₂) – triatomic36.9428.461.30
Methane (CH₄) – polyatomic35.6927.381.30

Why Cp is Greater than Cv

When heat is added at constant pressure, the system expands and does work on the surroundings. Therefore, extra energy is required to account for the work done. At constant volume, no work is performed, so all heat goes into increasing internal energy. Hence, \(C_p > C_v\). The difference is exactly \(R\) for ideal gases, as derived above.

Pressure-Volume diagram: Isobaric vs Isochoric heating processes.

[Graph showing constant volume (vertical line) and constant pressure (horizontal line) processes; area under isobaric indicates work done.]

Interactive Calculators

Compute γ and verify Cp – Cv = R

Enter Cp and Cv to compute γ = Cp/Cv and check Cp – Cv ≈ R (8.314).

Specific Heat Capacity Calculator

Enter Q, m, and ΔT to calculate specific heat capacity s = Q/(m·ΔT).

Applications of Heat Capacity

  • Calorimetry: Measuring heat changes in chemical reactions (coffee-cup calorimeter, bomb calorimeter).
  • Material design: High heat capacity materials (water) used as coolants; low heat capacity metals heat up quickly.
  • Atmospheric science: Oceans moderate climate due to high specific heat of water.
  • Engineering: Design of heat exchangers, engines, and thermal storage systems.

Summary of Key Equations

\[ C = \frac{\Delta Q}{\Delta T} \]
\[ s = \frac{C}{m} = \frac{1}{m}\frac{\Delta Q}{\Delta T} \]
\[ Q = n C_m \Delta T \]
\[ C_p = \left(\frac{\partial H}{\partial T}\right)_P,\quad C_v = \left(\frac{\partial E}{\partial T}\right)_V \]
\[ C_p – C_v = R \]
\[ \gamma = \frac{C_p}{C_v} \]
Complete Lecture: Heat Capacity, Cp, Cv & Derivation (Urdu/Hindi)

Watch this detailed lecture to master the concepts of heat capacity, Cp, Cv, and the relation Cp – Cv = R.

© 2026 — Comprehensive guide on Heat Capacity. All derivations, tables, and calculators included.

Download Complete Notes Below

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top