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Schrödinger Wave Equation for 3D Particle in a Box | Derivation

Schrödinger Wave Equation for a 3D Particle in a Box

Complete step-by-step derivation of the three-dimensional particle in a box model, including separation of variables, boundary conditions, normalization, quantum numbers, probability density, energy quantization and solved examples.

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1. Introduction to the Particle in a Three-Dimensional Box

The Schrödinger wave equation for a 3D particle in a box is one of the most important models in introductory quantum mechanics. It describes the behavior of a quantum particle confined to a finite region of space by perfectly rigid walls. Although the model is idealized, it provides a mathematical foundation for understanding quantum confinement, energy quantization, quantum wells, nanostructures and other systems.

In this model, a particle of mass m is confined inside a rectangular box having dimensions a, b and c along the x, y and z directions. The potential energy inside the box is taken to be zero, while the potential outside is infinitely large. Therefore, the particle cannot escape from the box.

The potential-energy function is written as:

\[ V(x,y,z)= \begin{cases} 0, & 0(1)

Because the potential is infinite at the walls, the wavefunction must become zero at every boundary. This condition is the key reason that only certain wavelengths and energies are allowed.

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Figure 1: Schematic representation of a particle confined inside a three-dimensional rectangular box.

2. Time-Independent Schrödinger Equation in Three Dimensions

For a non-relativistic particle, the Hamiltonian operator contains the kinetic-energy operator and the potential-energy function. In three dimensions, the Hamiltonian is:

\[ \hat{H} = -\frac{\hbar^2}{2m}\nabla^2+V(x,y,z) \] (2)

Here, the Laplacian operator is:

\[ \nabla^2= \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2}. \] (3)

The time-independent Schrödinger equation is obtained from:

\[ \hat{H}\psi=E\psi. \] (4)

Substituting the Hamiltonian gives the three-dimensional Schrödinger equation:

\[ -\frac{\hbar^2}{2m} \left( \frac{\partial^2\psi}{\partial x^2} + \frac{\partial^2\psi}{\partial y^2} + \frac{\partial^2\psi}{\partial z^2} \right) +V\psi = E\psi. \] (5)

Rearranging the equation:

\[ \frac{\partial^2\psi}{\partial x^2} + \frac{\partial^2\psi}{\partial y^2} + \frac{\partial^2\psi}{\partial z^2} + \frac{2m}{\hbar^2}(E-V)\psi =0. \] (6)

3. Wavefunction Outside the Box

Outside the rectangular box, the potential energy is infinite. A physical particle with finite total energy cannot occupy a region where the potential is infinitely large. Therefore, the probability of finding the particle outside the box is zero.

Mathematically, the boundary condition is:

\[ \psi(x,y,z)=0 \qquad \text{outside the box}. \] (7)

The same condition applies to the walls. Therefore:

\[ \psi(0,y,z)=\psi(a,y,z)=0 \] (8)
\[ \psi(x,0,z)=\psi(x,b,z)=0 \] (9)
\[ \psi(x,y,0)=\psi(x,y,c)=0. \] (10)
Important: These boundary conditions are responsible for the quantization of the particle’s allowed wavelengths and energy levels.

4. Schrödinger Equation Inside the 3D Box

Inside the box, the potential energy is zero: \(V=0\). Therefore, equation (6) becomes:

\[ \frac{\partial^2\psi}{\partial x^2} + \frac{\partial^2\psi}{\partial y^2} + \frac{\partial^2\psi}{\partial z^2} + \frac{2mE}{\hbar^2}\psi =0. \] (11)

Define:

\[ k^2=\frac{2mE}{\hbar^2}. \] (12)

The equation then takes the simpler form:

\[ \frac{\partial^2\psi}{\partial x^2} + \frac{\partial^2\psi}{\partial y^2} + \frac{\partial^2\psi}{\partial z^2} + k^2\psi =0. \] (13)

To solve this partial differential equation, we use the separation of variables method. Assume that the total wavefunction can be written as a product of three independent functions:

\[ \psi(x,y,z)=X(x)Y(y)Z(z). \] (14)

Substituting this expression into equation (13), dividing by \(XYZ\), and separating the variables gives:

\[ \frac{1}{X}\frac{d^2X}{dx^2} + \frac{1}{Y}\frac{d^2Y}{dy^2} + \frac{1}{Z}\frac{d^2Z}{dz^2} + k^2=0. \] (15)

Since each term depends on a different coordinate, each part can be assigned a separation constant:

\[ \frac{1}{X}\frac{d^2X}{dx^2}=-k_x^2, \qquad \frac{1}{Y}\frac{d^2Y}{dy^2}=-k_y^2, \qquad \frac{1}{Z}\frac{d^2Z}{dz^2}=-k_z^2. \] (16)

The three wave numbers satisfy:

\[ k_x^2+k_y^2+k_z^2=k^2=\frac{2mE}{\hbar^2}. \] (17)

5. Solving the x-Direction Equation

The x-dependent differential equation is:

\[ \frac{d^2X}{dx^2}+k_x^2X=0. \] (18)

Its general solution is:

\[ X(x)=A\sin(k_xx)+B\cos(k_xx). \] (19)

At \(x=0\), the wavefunction must vanish:

\[ X(0)=B=0. \] (20)

Therefore:

\[ X(x)=A\sin(k_xx). \] (21)

At the opposite wall \(x=a\):

\[ X(a)=A\sin(k_xa)=0. \] (22)

For a non-zero wavefunction, this requires:

\[ k_xa=n_x\pi, \qquad n_x=1,2,3,\ldots \] (23)

Thus:

\[ k_x=\frac{n_x\pi}{a}. \] (24)

Normalization requires:

\[ \int_0^a|X(x)|^2dx=1. \] (25)

This gives the normalized x-direction wavefunction:

\[ X_{n_x}(x) = \sqrt{\frac{2}{a}} \sin\left(\frac{n_x\pi x}{a}\right). \] (26)

The same mathematical procedure is applied independently to the y and z directions.

6. Solutions in the y and z Directions

Applying the boundary conditions at \(y=0\) and \(y=b\), the normalized solution along the y-axis is:

\[ Y_{n_y}(y) = \sqrt{\frac{2}{b}} \sin\left(\frac{n_y\pi y}{b}\right), \qquad n_y=1,2,3,\ldots \] (27)

Similarly, applying the conditions at \(z=0\) and \(z=c\):

\[ Z_{n_z}(z) = \sqrt{\frac{2}{c}} \sin\left(\frac{n_z\pi z}{c}\right), \qquad n_z=1,2,3,\ldots \] (28)

Each direction therefore contributes its own quantum number. A state of the three-dimensional particle is identified by the set:

\[ (n_x,n_y,n_z). \] (29)

7. Total Wavefunction of a Particle in a 3D Box

Multiplying the three normalized one-dimensional solutions gives the complete normalized wavefunction:

\[ \psi_{n_xn_yn_z}(x,y,z) = \sqrt{\frac{8}{abc}} \sin\left(\frac{n_x\pi x}{a}\right) \sin\left(\frac{n_y\pi y}{b}\right) \sin\left(\frac{n_z\pi z}{c}\right). \] (30)

This is the central result of the 3D particle in a box derivation. The wavefunction describes the quantum state of the particle inside the box. It is zero outside the allowed region and satisfies all six boundary conditions.

The normalization condition is:

\[ \int_0^a\int_0^b\int_0^c |\psi|^2\,dx\,dy\,dz=1. \] (31)
Exam point: The quantum numbers \(n_x,n_y,n_z\) cannot be zero. Their allowed values are positive integers: 1, 2, 3, and so on.

8. Energy Quantization in a Three-Dimensional Box

From the separation of variables:

\[ k^2=k_x^2+k_y^2+k_z^2. \] (32)

Using the allowed values:

\[ k_x=\frac{n_x\pi}{a}, \qquad k_y=\frac{n_y\pi}{b}, \qquad k_z=\frac{n_z\pi}{c}, \] (33)

We obtain:

\[ k^2 = \pi^2 \left( \frac{n_x^2}{a^2} + \frac{n_y^2}{b^2} + \frac{n_z^2}{c^2} \right). \] (34)

Since:

\[ k^2=\frac{2mE}{\hbar^2}, \] (35)

the allowed energy values are:

\[ \boxed{ E_{n_xn_yn_z} = \frac{\hbar^2\pi^2}{2m} \left( \frac{n_x^2}{a^2} + \frac{n_y^2}{b^2} + \frac{n_z^2}{c^2} \right) } \] (36)

Using \(\hbar=h/(2\pi)\), the energy equation can also be written as:

\[ \boxed{ E_{n_xn_yn_z} = \frac{h^2}{8m} \left( \frac{n_x^2}{a^2} + \frac{n_y^2}{b^2} + \frac{n_z^2}{c^2} \right) } \] (37)

This equation demonstrates energy quantization. The particle cannot possess arbitrary energy values. Only energies corresponding to allowed combinations of the three quantum numbers are possible.

9. Ground State and Excited States

The lowest possible quantum numbers are:

\[ n_x=n_y=n_z=1. \] (38)

Therefore, the ground-state energy is:

\[ E_{111} = \frac{h^2}{8m} \left( \frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2} \right). \] (39)

The ground-state energy is not zero. This is an important result of quantum mechanics and is commonly called the zero-point energy of the confined particle.

Excited states are obtained by increasing one or more quantum numbers. For example, \((2,1,1)\), \((1,2,1)\), and \((1,1,2)\) represent different quantum states.

10. Particle in a Cubic Box

If the box has equal dimensions:

\[ a=b=c=L, \] (40)

the energy equation becomes:

\[ E_{n_xn_yn_z} = \frac{h^2}{8mL^2} \left( n_x^2+n_y^2+n_z^2 \right). \] (41)

A cubic box can have degenerate energy levels. Degeneracy means that different quantum-number combinations can produce the same energy.

Example:

The states \((2,1,1)\), \((1,2,1)\), and \((1,1,2)\) all give:

\[ n_x^2+n_y^2+n_z^2=4+1+1=6. \]

Therefore, these three states have the same energy in a cubic box:

\[ E=\frac{6h^2}{8mL^2}. \]

11. Probability Density of the 3D Wavefunction

The wavefunction itself does not directly represent a measurable probability. According to the Born interpretation, the probability density is given by \(|\psi|^2\).

\[ |\psi_{n_xn_yn_z}|^2 = \frac{8}{abc} \sin^2\left(\frac{n_x\pi x}{a}\right) \sin^2\left(\frac{n_y\pi y}{b}\right) \sin^2\left(\frac{n_z\pi z}{c}\right). \] (42)

The probability of finding the particle within a small volume element \(dV=dx\,dy\,dz\) is:

\[ dP=|\psi|^2\,dx\,dy\,dz. \] (43)

The total probability throughout the box must equal one:

\[ \int_0^a\int_0^b\int_0^c|\psi|^2\,dx\,dy\,dz=1. \] (44)
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Figure 2: Probability-density representation for the ground state in an \(xy\)-plane slice.

12. Solved Numerical Example

Consider an electron confined in a cubic box of side length \(L=1.0\,\text{nm}\). Find the ground-state energy.

For the ground state:

\[ n_x=n_y=n_z=1. \]

For a cubic box:

\[ E_{111}=\frac{3h^2}{8mL^2}. \]

Using:

  • \(h=6.626\times10^{-34}\,\text{J s}\)
  • \(m_e=9.109\times10^{-31}\,\text{kg}\)
  • \(L=1.0\times10^{-9}\,\text{m}\)

Substitution gives approximately:

\[ E_{111}\approx5.64\times10^{-20}\,\text{J}. \]

Converting joules to electronvolts using \(1\,\text{eV}=1.602\times10^{-19}\,\text{J}\):

\[ E_{111}\approx0.352\,\text{eV}. \]
Interpretation: Even when the electron is in its lowest possible quantum state, its energy is greater than zero. Reducing the box size increases the energy because the energy varies inversely with the square of the confinement length.

13. How Box Size Affects Particle Energy

The energy equation shows that confinement has a direct effect on the energy of a quantum particle. For a cubic box:

\[ E\propto\frac{1}{L^2}. \] (45)

Therefore, if the box becomes smaller, the allowed energy levels become farther apart. If the box becomes larger, the energy levels become more closely spaced. This concept is particularly important in nanoscale physics and semiconductor quantum structures.

The same mathematical idea appears in quantum wells, quantum wires and quantum dots, where particles can become confined over very small dimensions.

14. Degeneracy in a Three-Dimensional Box

Degeneracy occurs when different sets of quantum numbers correspond to the same energy. In a rectangular box with unequal dimensions, degeneracy is generally less common because the terms \(1/a^2\), \(1/b^2\), and \(1/c^2\) distinguish the three directions.

In a cubic box, the symmetry between the three directions makes degeneracy much more apparent. For example:

\[ E_{211}=E_{121}=E_{112}. \] (46)

This does not mean that the wavefunctions are identical. The states have different spatial dependence, but their energy eigenvalues are equal.

15. Important Features of the 3D Particle-in-a-Box Model

QuantityResult
Potential inside\(V=0\)
Potential outside\(V=\infty\)
Quantum numbers\(n_x,n_y,n_z=1,2,3,\ldots\)
WavefunctionProduct of three sine functions
Probability density\(|\psi|^2\)
Energy\(\frac{h^2}{8m}(\frac{n_x^2}{a^2}+\frac{n_y^2}{b^2}+\frac{n_z^2}{c^2})\)
Ground state\((1,1,1)\)
Ground-state energyNon-zero

16. Applications of the Particle in a 3D Box

The particle-in-a-box model is not simply a mathematical exercise. It introduces several fundamental concepts that are used throughout quantum physics.

Quantum Confinement

When particles are confined to nanoscale dimensions, their allowed energies become quantized. This principle is important for understanding nanotechnology and semiconductor structures.

Quantum Dots

Quantum dots are nanoscale structures where electrons and holes can experience strong spatial confinement. The particle-in-a-box model provides a useful starting approximation for understanding their discrete energy levels.

Quantum Wells and Wires

Semiconductor quantum wells and quantum wires restrict particle motion in one or more directions. Their energy spectra can be understood using extensions of the same separation-of-variables approach.

Foundation of Quantum Mechanics

The model demonstrates wave-particle duality, boundary conditions, normalization, eigenvalues, eigenfunctions, quantum numbers and probability interpretation. These concepts are essential before studying more advanced quantum systems.

17. Common Mistakes in Particle-in-a-Box Problems

  1. Using zero as a quantum number: \(n_x,n_y,n_z\) must be positive integers.
  2. Forgetting the three dimensions: The total energy contains contributions from x, y and z.
  3. Using the wrong box dimensions: Each quantum number must be paired with the correct side length.
  4. Assuming ground-state energy is zero: The lowest allowed state has \(n_x=n_y=n_z=1\), so the energy remains positive.
  5. Confusing wavefunction and probability density: The measurable probability density is proportional to \(|\psi|^2\), not simply \(\psi\).
  6. Ignoring normalization: A physically acceptable probability distribution must integrate to one.

18. Frequently Asked Questions

What is the Schrödinger equation for a particle in a 3D box?

It is the time-independent Schrödinger equation applied to a particle confined inside a three-dimensional infinite potential well. Inside the box, \(V=0\), leading to a three-dimensional differential equation involving the x, y and z second derivatives of the wavefunction.

What are the quantum numbers for a particle in a 3D box?

Three quantum numbers are required: \(n_x\), \(n_y\), and \(n_z\). Each is a positive integer: 1, 2, 3, and so on.

What is the energy formula for a 3D particle in a box?

The allowed energy is: \[ E_{n_xn_yn_z} = \frac{h^2}{8m} \left( \frac{n_x^2}{a^2} + \frac{n_y^2}{b^2} + \frac{n_z^2}{c^2} \right). \]

Why does the wavefunction become zero at the walls?

The walls represent an infinite potential barrier. A finite-energy particle cannot exist in a region where the potential is infinite, so the wavefunction must vanish at the boundaries.

What is the ground state of a 3D particle in a box?

The ground state corresponds to \(n_x=n_y=n_z=1\), written as the state \((1,1,1)\).

What causes degeneracy in a 3D box?

Degeneracy occurs when different quantum-number combinations produce the same energy. It is especially common in a cubic box because of its high spatial symmetry.

Why is the ground-state energy not zero?

The boundary conditions permit only positive integer quantum numbers. The smallest allowed combination is \((1,1,1)\), which produces a positive energy. This is an example of quantum confinement and zero-point energy.

19. Video Lecture on Particle in a 3D Box

Complete Schrödinger Equation Derivation in Urdu/Hindi

Step-by-step explanation of separation of variables, boundary conditions, normalization, quantum numbers and energy quantization.

20. Quick Revision of the Schrödinger Wave Equation for a 3D Box

The complete derivation can be summarized in a few essential results. A particle is confined to a rectangular region with infinite potential walls. Inside the box, the potential is zero, so the time-independent Schrödinger equation becomes a three-dimensional Helmholtz-type equation.

\[ \boxed{ \psi_{n_xn_yn_z} = \sqrt{\frac{8}{abc}} \sin\left(\frac{n_x\pi x}{a}\right) \sin\left(\frac{n_y\pi y}{b}\right) \sin\left(\frac{n_z\pi z}{c}\right) } \]
\[ \boxed{ E_{n_xn_yn_z} = \frac{h^2}{8m} \left( \frac{n_x^2}{a^2} + \frac{n_y^2}{b^2} + \frac{n_z^2}{c^2} \right) } \]

These two equations are the most important formulas to remember for examination questions involving the particle in a three-dimensional box. The wavefunction describes the allowed quantum state, while the energy equation gives the corresponding quantized energy.

For more physics lessons, chemistry concepts, exam preparation material and educational resources, visit CogitaVerse .

21. Conclusion

The Schrödinger wave equation for a 3D particle in a box provides one of the clearest demonstrations of how quantum mechanics differs from classical physics. A particle confined within rigid boundaries cannot have arbitrary energy. Instead, the boundary conditions restrict the allowed wavefunctions and produce discrete energy levels.

By applying separation of variables, the three-dimensional problem can be reduced to three independent one-dimensional equations. Solving these equations and applying the boundary conditions produces the normalized wavefunction and the quantized energy expression. The three quantum numbers \(n_x\), \(n_y\), and \(n_z\) identify the allowed states.

Understanding this derivation is essential for students studying quantum mechanics, modern physics, atomic physics, nanotechnology and semiconductor physics. It also provides the mathematical foundation for more advanced models of quantum wells, wires and dots.

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